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Directional Derivatives and the Gradient Vector
Consider the surface S with equation and let . Then the point lies on S. What is the rate of change of at () in the direction of an arbitrary unit vector u = ( ) ?
Suppose the vertical plane that passes through P in the direction of u intersects S in a curve C . If C has a tangent line at P then the slope of the tangent line T to C at P is the rate of change of in the direction of u , which is called the directional derivative of at ( ) in the direction of u , denoted by .
Hence
,
if the limit exists.
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Notice that for u = ( ), and for u = ( ), .
On the other hand, if we define a function g of single variable t by
,
then
g ' (0) = = .
If is a differentiable function of and , by Chain Rule, we have
g ' ( t ) = ,
Put , we get
.
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So we have the following theorem :
Theorem
If is a differentiable function of and , then has a directional derivative in the direction of any unit vector u = ( ) and
Note that the theorem is also true if is a differentiable function of three variables.
In terms of vector functions, the curve C obtained by intersection of the vertical plane that passes through P in the direction of u with S can be described by the vector function
F (t) = ( )
and the tangent vector T of C at P is given by
F '(0) = ( ).
However,
the directional derivative in the direction of u = ( ) at ( ) is the rate of change of at ( ) in the direction of u which is the third component of F '(0).
Let , be the curves obtained by intersection of the vertical planes , , respectively. Then the tangent vectors of , at P are
= ( ) and = ( ), respectively.
The above theorem says that , which also indicates that , , lies on the same plane ( the tangent plane of S at P ).
If is a function of and , then the gradient of is the vector function defined by
So if is differentiable, then = . u for any unit vector u .
If angle between u and ( ) is , then we have
= | ( ) | | u | | ( ) |.
If is a function of three variables, then the gradient of is defined by
and it is also true that if is differentiable, then f ( x ) = ( x ) u for any unit vector u .
Therefore, we have
Theorem
If is a function of two or three variables, then the maximum value of the directional derivative f( x ) is |(x)| and it occurs when u has the same direction as (x).
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Let C is a level curve of f , suppose that C has the vector equation r (t) = (), that is, for some constant k . If and f are all differentiable, by Chain Rule, we get
+ .
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This says that the gradient vector ( ) is perpendicular to the tangent vector r ' ( ) to C .
The gradient of a function satisfies the following properties :
1. points in the direction of maximum increase of the function.
2. | | is the rate of increase of in the direction of maximum increase.
3. is perpendicular to each level curve of the function .
4. | | is inversely proportional to the spacing between the level curves.
Suppose S is a surface with equation , that is, it is a level surface of a function F of three variables, let be a point on S . Let C be a curve that lies on the surface S and passes through point P, say C is given by the vector function
r (t) = ( ) with r () = ( ) .
Since C lies on S , we have
.
Suppose that and F are all differentiable, by Chain Rule, we get
+ + ,
that is, . r ' ( t ) = 0 for all t.
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In particular,
( ) . r ' ( ) = 0.
This says that the gradient vector ( ) is perpendicular to the tangent vector r ' ( ) to any curve C on S that passes through P .
If ( ) is a nonzero vector, then it is a normal vector of the tangent plane to S at P . In this case, the equation of the tangent plane is given by
.
The normal line to S at P , which is the line passing through P and perpendicular to the tangent plane, is given by the symmetric equations
= .
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Example Find the equation of the tangent plane and normal line at ( ) to the ellipsoid
Note that the ellipsoid is a level surface of the function
Therefore, we have
, ,
, ,
Hence the equation of the tangent plane is
and the symmetric equations of the normal line are
=